Current is always something per second as its about flow so I’m fine with C/s there.
Thanks for the power association for p: that makes it easier to remember.
Not that it really matters, but the so-called p is the greek letter rho ;-)
Which in this instance is the resistivity (“resistance coefficient”) of the material, so yes Jeroen Wiert Pluimers, it’s a material constant
Sorry but you seem to be putting 2 ideas together.The diagram can be interpreted in DC form OR ac form but never together which is trying to be done. DC is pure V=IR and that’s it. If you want to Quote ac formula you can add power factor,cable resistance factor and phase difference.So the diagram seems to be putting forward one diagram and should have had 2.one for DC and one for ac.
Ken Harragon I guess you’re talking to me?
You’re right, so ofc I can’t argue against that.
I’m just commenting on the formula for resistance presented on the poster.. Nothing more
I am an electrical engineer and there seemed to be confusion on R i was trying to help. It appears you were trying to use R as the resistance of the cable only Which indeed has validity.
Ken Harragon and methods. just saying; however Kenneth the difference is methods generally apply to real world applications – that versus theoretical nonsense.
you have concepts and applications. DC is usually straight forward but ac is taking into losses as well as phase difference and power factor. ac=ir*pf.
So what’s the p in the Ohm formula?
I do the the length over area. Is p a material constant?
P=Watts
I am not the poster but p=power factor which is usually 1 so it is usually left out and current A= v/r not c/s whatever they are.
Current is always something per second as its about flow so I’m fine with C/s there.
Thanks for the power association for p: that makes it easier to remember.
Not that it really matters, but the so-called p is the greek letter rho ;-)
Which in this instance is the resistivity (“resistance coefficient”) of the material, so yes Jeroen Wiert Pluimers, it’s a material constant
Gaute Wilhelmsen Seljestad thanks. On mobile it just looks like a p, but it’s a ρ.
Sorry but you seem to be putting 2 ideas together.The diagram can be interpreted in DC form OR ac form but never together which is trying to be done. DC is pure V=IR and that’s it. If you want to Quote ac formula you can add power factor,cable resistance factor and phase difference.So the diagram seems to be putting forward one diagram and should have had 2.one for DC and one for ac.
Ken Harragon I guess you’re talking to me?
You’re right, so ofc I can’t argue against that.
I’m just commenting on the formula for resistance presented on the poster.. Nothing more
I am an electrical engineer and there seemed to be confusion on R i was trying to help. It appears you were trying to use R as the resistance of the cable only Which indeed has validity.
Ken Harragon I could never wrap my head around AC and phase difference. Do you know any diagram that could help me out?
http://www.animations.physics.unsw.edu.au/jw/AC.html
good article just look past the maths and take in the concepts because the maths is only used in design mostly.
Ken Harragon and methods. just saying; however Kenneth the difference is methods generally apply to real world applications – that versus theoretical nonsense.
you have concepts and applications. DC is usually straight forward but ac is taking into losses as well as phase difference and power factor. ac=ir*pf.
Ken Harragon wow, that page is a lot to take. I’ll try to find some time to get through it at a pace I can “get” it. Thanks!
Ken Harragon You are correct Kenneth.
Neat